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LnZ= lna nlnX−mlnY ∼N(µ lnZ,σ2 Z) where µ lnZ= lna nµ lnX−mµ lnY = lna nlnx m −mlny m and σ2 lnZ = (nσ lnX) 2 (mσ lnY) 2 = n2 ln(1 c2 X) m 2 ln(1 c2 Y) = ln(1 c 2 Z) CC BYNCND PSH, HPG, JTS Probability Distributions 5 Uniform X∼Ua,b Triangular X∼T(a,b,c) aU » I y c M i ( ï x ) Ð " ¹ ô I y ¤ æ ;­ U ® * ;

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